EPSO/AST/133/14 competition

Written on 3 February 2015, 03:32pm

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Because the Notice of Competition and the official comments on the blog are not very clear, here is a visual representation of the competition steps:
AST ICT 133 flow chart
Made with SchemeIt

Talent screener works in 2 stages:
– first a score is calculated based solely on the yes/no answers
– second a score is calculated based on weighted average (each criteria has a number of points assigned).
Like that (note – the talent screener questions below refer to an old competition):
talent screener stages

There, I fixed it.

Amazon interview question

Written on 15 February 2014, 12:18am

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From Stack Exchange:

• 50% of all people who receive a first interview receive a second interview
• 95% of your friends that got a second interview felt they had a good first interview
• 75% of your friends that DID NOT get a second interview felt they had a good first interview
If you feel that you had a good first interview, what is the probability you will receive a second interview?

The easiest way (at least for me) to go is to turn those percentages into some real numbers. For instance:
– 100 friends that got a second interview; 95 of them felt that they had a good first interview
– 100 friends that did NOT get a second interview; 75 of them felt that they had a good first interview.
Now, if you ignore the fact that it’s pretty difficult to have 200 friends (let alone the fact that they all applied for a job at Amazon 🙂 ), the numbers say that:
– 95 + 75 = 170 friends had a good feeling after the first interview
– but only 95 of them had a second interview
– so the probability of you having a second interview is 95 / 170 = 0.558.
In other words, if you felt good after the first interview, you have more than 50% chances that you get a second interview.

Image: HollywoodReporter.com

Now, if you come up with the answer 55.8% to your Amazon interviewer, I think you would get some points. But not all of them. Because in the logic below there are 2 hidden assumptions: