Geometric problem

Written on 24 May 2013, 11:07am

Tagged with:

You have 3 non-colinear points (they are not all on the same line).
Draw the circle that contains all the 3 of them.

Solution:
Draw the perpendicular bisectors of any 2 segments formed using the 3 points. The center of the circle is the intersection of the perpendicular bisectors.

Link: http://www.mathopenref.com/
proof

Leave a response